.co.uk domains and hosting

[hostroyal]

Basically i dont know if its in the right forum but here goes. I was wondering why most american people hesitate to buy of a .co.uk domain. I was thinking of creating a version of my site with american prices but using the same domain anme and it was pointed out to me by brian that most americans wont buy hosting if its a uk domain. Would you recomend that i buy a new domain .com has been taken in my desired domain or stick to my current domain? Also why do Americans not like .co.uk domains

[wisehosting]

We have quite a few american clients who have purchased through our .co.uk website. However many propective clients are worried about the different time zone for support, taking payments in £ instead of $usd etc and would prefer to buy from a non co.uk domain in $usd.

I think it's more a "feeling secure" thing. We are drawing up plans to make our company more appealing to US and abroad markets for this reason.

[hostroyal]

Thanks for your reply brian, i kind of get the idea. Any one else with any ideas?

[Chicken]

Though we love you guys (and really we do), .co.uk probably seems like a "foreign domain" -which I suppose it is, while .com seems more domestic (or maybe the word is generic, I don't know). While I personally wouldn't have an issue buying services through a .co.uk domain or a .net domain, many people see .com as king (regardless of where the company is located, etc.) I have noticed that people are getting more used to other extensions though.

Do you UK'ers (in general) feel that .com is foreign?

[wisehosting]

Do you UK'ers (in general) feel that .com is foreign?
Personally - No I don't. But I do get frustrated at the lack of uk companies with no co.uk domain - makes the google search "uk only" searches difficult when you need to buy something within the uk :-)

[hostroyal]

personally no as i do see it as a standard domiain.

Chicken any ideas for when .com and net has been taken for hostroyal?
Im planning on keeping .co.uk aswell but also haveing a US site in $